Topic: Regular Tetrahedron
Answers to Common Questions
What is the volume of the regular tetrahedron?
given the length of a side as S, the volume is: SQRT(2)*S 3 /12 Where SQRT(2) is the square root of 2 (~1,414) and S 3 is the length of a side cubed. Read More »
Source: http://wiki.answers.com/Q/What_is_the_volume_of_the_regular_tetra...
What is regular tetrahedron?
( ′reg·yə·lər ′te·trə′hē·drən ) (mathematics) A regular polyhedron of four faces. Read More »
Source: http://www.answers.com/topic/regular-tetrahedron-mathematics
What's the definition of regular tetrahedron?
regular tetrahedron: a tetrahedron with four equilateral triangular faces Read More »
Source: http://www.kgbanswers.com/whats-the-definition-of-regular-tetrahe...
Featured Content: Regular Tetrahedron
In geometry, a tetrahedron (plural: tetrahedra) is a polyhedron composed of four triangular faces, three of which meet at each vertex. It has six edges and four ... More »
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Answers to Other Common Questions
1. a tetrahedron with four equilateral triangular faces Read More »
Source: http://www.audioenglish.net/dictionary/regular_tetrahedron.htm
If the length of each edge is s cm then the area of each face is sqrt(3)*s/4 square cm. Since there are 4 such faces, the total area is sqrt(3)*s cm 2 . Read More »
Source: http://wiki.answers.com/Q/How_do_you_find_lateral_area_of_a_regul...
Sorry, I don't recognize "digedl." A regular tetrahedron has angles that measure... Read More »
Source: http://www.chacha.com/question/how-many-digedl-angles-are-in-a-re...
Sorry but i'll need more information, such as the other lengths ... Read More »
Source: http://www.chacha.com/question/what-is-the-volume-of-a-regular-te...
The exact surface area of a r... Read More »
Source: http://www.chacha.com/question/what-is-the-approximate-surface-ar...
You mean the centroid of the regular tetrahedron (the common point of its medians - the regular tetrahedron is the only Platonian Solid without center of symmetry), right? You can find all necessary information in a Wiki article, follow the... Read More »
Source: http://answers.yahoo.com/question/index?qid=20120227151049AACPWdr
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