Topic:

Removable Discontinuity

Not finding your answer? Try searching the web for Removable Discontinuity
Answers to Common Questions
a non removable discontinuity is one that you can't "repair" and example would be an asymptote as you just said. it can also be a place where the function is discontinuos and cant be given a new point to make it continuos.
http://answers.yahoo.com/question/index?qid=2009110415...   See entire page »
No; At that point, it's an asymptote.
http://answers.yahoo.com/question/index?qid=2008112519...   See entire page »
Take the limit of the function as x approaches 3...you may need to do a little algebra to simplify the expression...
http://answers.yahoo.com/question/index?qid=2008080917...   See entire page »
Answers to Other Common Questions
I'll show you two.・ 1. The idea is that you want to have (x-2) in the denominator of a fraction since that will certainly ... ・ 2. Here is another easy one. We know that y = sin(x)/x is discontinuous at x=0, but that lim x-->0 of ...
http://answers.yahoo.com/question/index?qid=20080907192...
yes, i suppose you do, since this would maintain the idea of the integral being the area under a curve. To form this area physically, you'd join the ends of the discontinuity with a vertical line; this would correspond to just 'slicing up' ...
http://answers.yahoo.com/question/index?qid=20090416081...
No. The discontinuity is only removable if the function approaches the same finite value both sides of that x value. This means that it doesn't go off to infinity approaching a vertical asymtote. This applies to any kind of function not jus...
http://answers.yahoo.com/question/index?qid=20090201113...
If a function has a removable discontinuity at , that means these things. All the limits above are finite. Basically, if there is a removable discontinuity at , the function has almost everything needed to be continuous there, but the funct...
http://www.physicsforums.com/showthread.php?t=262486
Not sure about the first but I would have thought the second function would encounter problems at 3 and -3 since the denominator will become zero. I've not come across the concept of removable discontinuities but I would suggest this would ...
http://answers.yahoo.com/question/index?qid=20090909194...
The limit of taxes as Obama's government expansion approaches infinity is equal to your pay check.
http://answers.yahoo.com/question/index?qid=20090422074...