Topic: Simplifying Logarithms
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Answers to Common Questions
How do you simplify logarithm equations?
well....... you go and throw your math homework or whatever you have in the garbage and its solved... thats about the only way i could figure out how to do it lol Read More »
Source: http://wiki.answers.com/Q/How_do_you_simplify_logarithm_equations
How to simplify this logarithmic function?
Hopefully that's: log(base=3) of 20 = logз[20] = 9 ^ ( logз[20] ) = (3²) ^ ( logз[20] ) ... in this case the exponents multiply = 3 ^ ( 2 • logз[20] ) = 3 ^ ( 2 • logз[20] ) ... move the multiplier "2" inside the log as an expon... Read More »
Source: http://answers.yahoo.com/question/index?qid=20111121134630AAv5oqy
How to simplify this logarithm?
Using a couple of the properties of logs: nLog u = log (u^n) and log u + log v = log (uv) 2log(x+9) + 3log(x^2 - 1) = log(x+9)^2 + log(x^2 - 1)^3 = log [(x+9)^2 * (x^2 - 1)^3] simplify inside the brackets gives: = log (x^6 - 3x^4 +4x^2 + 18... Read More »
Source: http://answers.yahoo.com/question/index?qid=20110121061033AAynIfp
More Common Questions
Answers to Other Common Questions
ln (a^b) = b*ln(a) ln(a*b) = ln(a) + ln(b) ln(a/b) = ln(a) - ln(b) So let's go and try it: ln ([(x - 3)^4(x^2 + 1)] / (2x + 5)^3)^(1/5) = (1/5) * ln ([(x - 3)^4(x^2 + 1)] / (2x + 5)^3) = (1/5) * ( ln [(x - 3)^4(x^2 + 1)] - ln ((2x + 5)^3) )...
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Source: http://answers.yahoo.com/question/index?qid=20091018114826AAJ2d4k
Simplify log2(8). This log is equal to some number y: log2(8) = y. The Relationship says:2 y = 8 That is, log2(8), also known MORE
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Source: http://www.chacha.com/question/how-do-you-simplify-base-10-logari...
343 = 7^3 and √7 = 7 ^ 1/2 so 343√7 = 7^3•7^1/2 = 7^ (3 + 1/2) = 7 ^ (7/2) and log7 (7 ^ (7/2)) is just 7/2 and 5 • 7/2 = 35/2 6 to the 5log (small/sub)6 x+3 power becomes (6 to the [ log (small/sub)6 x+3 power ]) to the 5 power 6 to the lo...
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Source: http://answers.yahoo.com/question/index?qid=20090510174035AAN45ys
Yay, I love logs! :) When you subtract logs, the combined log is a division 1. log 12 - log 3 log 12/3 log 4 When you add logs, the combined log is a multiplication 2. 3 log_11 5 + log_11 7 3 log_11 5*7 3 log_11 35 When there is a power, th...
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Source: http://answers.yahoo.com/question/index?qid=20090227125918AAEI4hA
does that mean x to the 3 (as in exponents) you cant do anything if so. unless it was say x^2 - 16 which is a perfect square, its (x-4)(x+4), or if you expand it out (x+x+x) - (x+x) = (x)
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Source: http://answers.yahoo.com/question/index?qid=20090127155524AAM8yj8
I think you are missing parentheses a.) ln(1+X / X) + ln(X / X-1) - ln(X^2 - 1) I'll solve ln((1+x)/x) + ln(x/(x - 1) - ln(x^2 - 1) = ln[(1+x)/x)(x/(x-1)/(x^2 -1)] = ln{[(1+x)/(x - 1)]/[(x +1)(x - 1)]} = ln[1/(x-1)^2] = ln 1 - ln[(x -1)^1] ...
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Source: http://answers.yahoo.com/question/index?qid=20081025120006AAhcqWU
I will use the notation log_b(a) to indicate the logarithm base b of a. log_5(25) - log_4(1/16) - log_7(7) = log_5(5^2) - log_4(4^-2) - log_7(7^1) = 2 - (-2) - 1 = 3
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Source: http://answers.yahoo.com/question/index?qid=20111124105219AAoInfW
