Topic: Tangential Acceleration
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What is tangential acceleration?
( tan′jen·chəl ak′sel·ə′rā·shən ) (mechanics) The component of linear acceleration tangent to the path of a particle moving in a circular path. Read More »
Source: http://www.answers.com/topic/tangential-acceleration
What are the tangential and normal components of acceleration?
Well if you are familiar with calculus the projection of acceleration vector a(t)on to the Tangent unit vector T(t), that is tangential acceleration. While the projection of acceleration vector a(t) on to the normal vector is the normal acc... Read More »
Source: http://wiki.answers.com/Q/What_are_the_tangential_and_normal_comp...
How tangential acceleration produced in a body?
Tangential acceleration is d/dr mcV = mc dVcdt = mdv/dt. The tangential acceleration is dV/dt is produced form the Vector Energy (mcV, the "Dark Energy"). Newton "added" the tangential acceleration as " dV/dt" to balance he Gradient acceler... Read More »
Source: http://wiki.answers.com/Q/How_tangential_acceleration_produced_in...
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Answers to Other Common Questions
Vt=w*r where; * is multiply Vt is tangential velocity w is omega(angular mometum) r is radius
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Source: http://wiki.answers.com/Q/What_is_tangential_velocity_and_tangent...
Radial acceleration is v^2/r Tangential acceleration is r(angular acceleration) r=radius v=velocity=r(angular velocity)
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Source: http://answers.yahoo.com/question/index?qid=20111031202256AA0yhfp
dw = (2π/60)*95 - (2π/60)*65 = 9.948 - 6.807 = 3.14159 rad/sec α = dw/dt = 0.314159 rad/sec² Ap = α*Rp = 0.314159*0.20 = 0.0628 m/s² Θ = d(w²)/(2α) = (9.948² - 6.807²)/(2*0.314159) = 83.77 rad Lc = Rc*Θ = (0.21/2)*83.77 = 8.8 meers
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Source: http://answers.yahoo.com/question/index?qid=20120328124523AAJGt0P
Let: w be the final angular speed, t be the time to reach that speed, alpha be the constant angular acceleration. a be the tangential acceleration of a point on the circumference, r be the radius. alpha = wt / 2 = (4.50 * 2pi * 3.20 / 2) ra...
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Source: http://answers.yahoo.com/question/index?qid=20081028125041AA1lQL5
tangential acceleration = (v^2)/r so in this case the tangential acceleration would be : (4m/s/s)^2 divided by radius in metres which is 0.5m So that is 16 divided by 0.5m which equals to 32m/s/s The answer is b.
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Source: http://answers.yahoo.com/question/index?qid=20120415230839AAiliaL
Assuming you're using m for meter, none of them are correct. a = Force/mass = N/kg
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Source: http://answers.yahoo.com/question/index?qid=20101022195406AAU6P4N
