Topic: Tartaglia Solves Cubic Equations
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How to solve cubic equation?
Take a look at this site: http://mathworld.wolfram.com/CubicFormul… Good luck! Read More »
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What is the cubic formula, used to solve cubic equations?
Cardano's formulae for solving algebraically the cubic equation is x^3+3x^2-1 = 0. More questions? Read More »
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When did taraglia first solve cubic equations
Cubic equations were known to the ancient Indians and ancient Greeks since the 5th century BC. Read More »
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Tartaglia Solves Cubic Equations
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3y^(3)+20y^(2)=7y Since 7y contains the variable to solve for, move it to the left-hand side of the equation by subtracting 7y from both sides. 3y^(3)+20y^(2)-7y=0 Factor out the GCF of y from each term in the polynomial. y(3y^(2))+y(20y)+y...
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Source: http://answers.yahoo.com/question/index?qid=20111211155903AAzjj1D
Mathematica can solve cubic equations exactly using the built-in command Solve[a3 x^3 + a2 x^2 + a1 x + a0 == 0, x]. The solution can also be expressed in terms of Mathematica algebraic root objects by first issuing Set Options.
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Just a thought.... By eyeballing the equation, we can see that the sum of the coefficients is equal to zero, which means that 1 is a root and that (x-1) is a factor. I suppose that you can then divide that polynomial by (x-1) to get a quadr...
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just readd that leonardo febunicci (spelling) may be the guy. however it also names others, so i am not 100%
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Source: http://wiki.answers.com/Q/What_person_is_generally_credited_with_...
http://webscripts.softpedia.com/script/S... get a program from this website http://www.daniweb.com/forums/thread4139...
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Source: http://answers.yahoo.com/question/index?qid=20080604152717AAomHEX
If you can't take out a common factor, as in x^3 -5x^2 +4x = x(x^2 -5x+4) =x(x-1)(x-4) you might be able to factor by grouping,as in x^3 -3x^2 +4x-12 =x^2(x-3) +4(x-3) =(x-3)(x^2+4), otherwise you have to use the rational root theorem and s...
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Source: http://answers.yahoo.com/question/index?qid=20120108155030AAi7ko5
