Q:

# What is the gram formula mass of (NH4)3 PO4?

A:

The molar mass of (NH4)3PO4 is 149.087 grams per mole. Finding this answer involves using the number of atoms of each element in the molecular formula for this compound and their atomic masses.

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From the molecular formula (NH4)3PO4, the number of atoms for each element is three atoms of nitrogen, twelve atoms of hydrogen, one atom of phosphorus and four atoms of oxygen. From the periodic table, the atomic masses for each element are nitrogen equals 14.0067 grams per mole, hydrogen is 1.00794, 30.973761 for phosphorus and oxygen is 15.9994.

To find the mass of the compound, which is ammonium phosphate, it is necessary to multiply the number of atoms of each element by their respective atomic mass and then add these quantities together: [(14.0067 grams/mol x 3) + (1.00794 grams/mol x 12 ) + (30.973761 grams/mol x 1) + (15.9994 grams/mol x 4)], which is equal to 149.087 grams per mole when rounded to the nearest thousandth.

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## Related Questions

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The formula (NH4)3PO4 does represent an ionic compound. (NH4)3PO4 is known as ammonium phosphide and it has a molar mass of 85.0891.

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The molar mass of Fe2O3, which is the chemical formula for iron(III) oxide, is 159.68 grams per mole. The molar mass is determined by adding together the atomic weight of each atom in the compound.

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NH4 is the chemical symbol for the ammonium ion. This ion has a positive charge, and is thus known as a cation. Ammonium ions can be formed by combining ammonia and acid in aqueous solution. Ammonium ions react quickly with most metals, forming salts.