The oxidation number for sulfur in SO2 is +4. To find this oxidation number, it is important to know that the sum of the oxidation numbers of atoms in compounds that are neutral must equal zero. In the compound sulfur dioxide (SO2), the oxidation number of oxygen is -2.Know More
To find the oxidation number of sulfur, it is simply a matter of using the formula SO2 and writing the oxidation numbers as S = (x) and O2 = 2(-2) = -4. Using the rule and adding the oxidation numbers in the compound, the equation becomes x +(-4 ) = 0. Solving for x, it is evident that the oxidation number for sulfur is +4.
In chemical compounds, an atom's oxidation number refers to the charge that atoms have if the compound consists of only ions. When writing compound formulas or reactions, there are rules used to assign oxidation numbers.Learn more about Chemistry
SO2, commonly known as sulfur dioxide, has an sp3 hybridization. The molecular geometry of sulfur dioxide consists of two oxygen atoms bonded to the central sulfur atom.Full Answer >
The oxidation number for NH3, also known as ammonia, is 0. Although the oxidation number of the nitrogen atom in the molecule is -3, the oxidation numbers for the three hydrogen atoms are equal to +3, so the two elements cancel each other out.Full Answer >
The oxidation number for NO3, or nitrate, is -1. This is because oxygen always has an oxidation number of -2. The three oxygen atoms have a combined oxidation of -6, corresponding to their electromagnetic charge and the lone nitrogen has a charge, or oxidation number, of +5.Full Answer >
Carbon monoxide is a neutral molecule; the oxidation number or state of carbon is +2 and oxygen is -2. The two possible oxidation numbers for oxygen are -1 and -2; the oxidation state -1 occurs in peroxides and is fairly uncommon, so the oxidation state of oxygen is -2.Full Answer >