The oxidation number for sulfur in SO2 is +4. To find this oxidation number, it is important to know that the sum of the oxidation numbers of atoms in compounds that are neutral must equal zero. In the compound sulfur dioxide (SO2), the oxidation number of oxygen is -2.
To find the oxidation number of sulfur, it is simply a matter of using the formula SO2 and writing the oxidation numbers as S = (x) and O2 = 2(-2) = -4. Using the rule and adding the oxidation numbers in the compound, the equation becomes x +(-4 ) = 0. Solving for x, it is evident that the oxidation number for sulfur is +4.
In chemical compounds, an atom's oxidation number refers to the charge that atoms have if the compound consists of only ions. When writing compound formulas or reactions, there are rules used to assign oxidation numbers.Learn More
The most common chemical formulas for chalk are CaCO3 (calcium carbonate) and CaO (calcium oxide). Chalk is a soft, porous sedimentary rock that is a form of limestone and is mainly composed of calcite (calcium carbonate).Full Answer >
Solid iodine consists of shiny bluish-black crystals, but iodine vapors are a purple gas. Iodine is named after the appearance of the iodine vapors, as "iodes" is the Greek word for purple.Full Answer >
Every atom is made up of a nucleus surrounded by electrons that orbit the nucleus. Electrons orbit the nucleus because they are attracted to the protons inside of the nucleus while simultaneously repelled by the other electrons.Full Answer >
Nitrogen triiodide is an extremely powerful contact explosive with the formula NI3. Small quantities of dry nitrogen triiodide explode with a loud snap and are set off by a light touch or vibration. Nitrogen triiodide is created through the reaction of iodine with ammonia.Full Answer >