en.wikipedia.org/wiki/Angle_bisector_theorem

In this diagram, BD:DC = AB:AC. In geometry, the angle bisector theorem is
concerned with the relative lengths of the two ... Let the angle bisector of angle A
intersect side BC at a point D between...

www.answers.com/Q/AC_plus_BC_could_equal_15

never. A+ :)).

www.artofproblemsolving.com/wiki/index.php?title=2002_AMC_12A_Problems

What would her answer have been had she worked the problem correctly? $\
mathrm{(A) ... arc of circle A is equal in length to a $30^\circ$ arc of ... and $(x+15
)^2 + y^2 = 81$ ... to meet $\overline{AC}$ ... and the perpendicular bisector of $
BC$ ...

www.erikthered.com/tutor/sat-math-hard-practice-quiz.pdf

How many red tomatoes were originally in the bag? (A) 12. (B) 15. (C) 18. (D) 24.
(E) 30 ... above is equal to a, and each term thereafter is 7 greater .... All of the
following could be a possible value of .... In the figure above, AC = 7 and AB = BC
.

www.cut-the-knot.org/pythagoras/index.shtml

Similarly, the area BC² of the square on side BC equals that of rectangle BMLD.
... This same configuration could be observed in a proof by tessellation.) ... Taking
AB = a, AC = b, BC = c and denoting BD = x, we obtain as above ..... has pointed
out that this same diagram is easily explained with a tessellation in proof #15.

www.umass.edu/preferen/Game Theory Evolving/GTE Public/GTE Answers.pdf

The numerator in this expression is equal to the probability that a1 is the lowest of
three ..... aŒaН D a.ac/ D 2=3, bŒaН D 0, and cŒaН D 1=3. Similarly, it is ... b.bc
/ C. 1. 2 b. : We can solve this for b, getting b D 24=69. The similar equation for.

mathforum.org/library/drmath/view/52861.html

I first noticed that I could get an expression including the required terms a^4, ... (a
+b+c)^2 = (a^2+b^2+c^2)+2(ab+ac+bc) and so (ab+ac+bc) ...

www.cut-the-knot.org/pythagoras/cos15.shtml

We can place side by side the right isosceles triangle ADE and the 30-60-90 ... In
\Delta ABC, AB = 1 + \sqrt{3} so that AC = BC = (1 + \sqrt{3}) / \sqrt{2}: ... Indeed,
assuming the side of the square equals 1, the altitude EF of \Delta ADE is found ...

aleph0.clarku.edu/~djoyce/elements/bookI/propI20.html

But DA equals AC, therefore the sum of BA and AC is greater than BC. Similarly
we can prove that the sum of AB and BC is also greater than CA, and the ... This
proposition on the triangle inequality, along with I.15 on vertical angles, allows us
...

aleph0.clarku.edu/~djoyce/java/elements/bookI/propI6.html

Since DB equals AC, and BC is common, therefore the two sides DB and BC ...
The converse would be “If two circles do not have the same center, then they cut
...