www.columbia.edu/itc/sipa/math/systems_linear.html

By setting first x and then y equal to zero it is possible to find the y intercept on ... If x = 0, then f(0) = 1 + .5(0) = 1. If y = 0, then f(x) = 0 = 1 + .5x. -.5x = 1. x = -2 ... If y = 0, then f(x) = 0 = 11 - 2x. 2x = 11. x = 5.5. The resulting data points are (0,11) and (5.5,0) ... From the graph it can be seen that these equations are equivalent.

jwilson.coe.uga.edu/EMT668/EMAT6680.Folders/Barron/unit/Lesson%205/5.html

Specifically, we graphed the two equations y = 2x + 5 and y = (-3/2)x + 2, and ... Now, we can set the right hand side of each equation equal to each other because they both equal y. ... x = 5y in the second equation, then x must also equal 5y in the first equation. .... Also, the point (0, 19/14) works, where x = 0 and y = 19/14.

www.khanacademy.org/math/cc-eighth-grade-math/cc-8th-systems-topic/cc-8th-systems-with-substitution/v/substitution-method-2

Learn to solve the system of equations y = -5x + 8 and 10x + 2y = -2 using ... x + y + z = –25 y = –8z x = 12z. And no, this isnt my homework. 5 Votes .... After you do so, you will find the B. Then substitute B in the first equation to find a. 6 Votes ..... y ^4 - 40y^2 + 144 = 0 ... How do I solve y=2x+7 and y=9x+8 using substitution?

www.khanacademy.org/math/cc-eighth-grade-math/cc-8th-systems-topic/cc-8th-systems-elimination/a/systems-of-equations-with-elimination

Key idea: Anytime we have two true equations, we can add or subtract them to create ... 2}} 4x−3y=17 Equation 24, x, minus, 3, y, equals, 17, space, space, space, space, space, space .... 8 &\gray{\text{Plug in x = 5 and y = 1}}\\\\ 8 &= 8 &\ gray{\text{Yes!} ..... Multiplying one of the equations by a constant, then using elimination.

www.montereyinstitute.org/courses/DevelopmentalMath/TEXTGROUP-1-19_RESOURCE/U13_L1_T2_text_final.html

Graph a linear equation using x- and y- intercepts. ... You can use a coordinate plane to plot points and to map various ... So if the rule of this pattern is that each y-coordinate is twice the corresponding x-value, then the ordered pairs (1.5, 3), ( 2.5, 5), and ... x values. 2x + 3. y values. 0. 2(0) + 3. 3. 1. 2(1) + 3. 5. 2. 2(2) + 3. 7. 3.

www.montereyinstitute.org/courses/Algebra1/COURSE_TEXT_RESOURCE/U04_L1_T2_text_final.html

We can use the characteristics of intercepts to quickly calculate them from the equation of a line. ... To find the y-intercept, we substitute 0 for x in the equation, because we ... Example. Problem. 3y + 2x. = 6. 3y + 2(0). = 6. 3y. = 6. = Answer. y. = 2 ... a line—we just have to plot the intercepts and then draw a line through them.

www.math-only-math.com/math-problem-solver.html

If you have any question which you find difficult to solve then you can fill-up the below ... 2. Complete the table for the given equation and graph the equation; x + 2y = 5 ... 2y = 5 2y/2 = 5/2 y = 5/2 (0, 5/2) Put the value of y = 0, x + 2 × 0 = 5 x = 5 (5, 0) ... 2x = 12 2x/2 = 12/2 x = 6. Therefore, x-intercept = (6, 0). 5. Find the x-and ...

www.analyzemath.com/math_questions/math_questions_2_sol.html

... then f -1(x) = Solution y = Log(x) if and only if x = 10 y. Interchange x and y y = 10 x. Hence ... Hence their exponents has also to be equal 3x - 1 = 4. Solve for x x = 5/3 ... The roots of the equation x / (x + 2) + 3 / (x - 4) = (4x + 2) / (x 2 - 2x - 8) are .... If Pi < x < 3 Pi/2, then sin(x) can be expressed in terms of tan(x) as follows

www.themathpage.com/alg/equation-of-a-line-2.htm

Example 1. Calculate the value of x when y = 0, that is, find the x-intercept of y = 2x + 10. Solution. On putting y = 0, we have to solve the equation,. 2x + 10, = 0. We have: 2x, = −10. x, = −5. ... a) When we have the equation of a straight line, how do we find the ... the same. Find the intercepts by putting x -- then y -- equal to 0.

www.algebra.com/algebra/homework/Linear-equations/Linear-equations.faq.question.159004.html

2x+y<10 x>0,y>0 .... x+y<8 -x -x ______. Y<-x+8 2x+y<10 -2x -2x ______ y<-2x+ 10 .. i need to graph this but i do not know how to do it. ... for both equations to be equal with the same values of x and y in each, x must = 2 and y must = 6. that would be .... then x + y < 8 becomes .5 + 8 which is not < 8 so it fails the test. let x = 6 ...