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en.wikipedia.org/wiki/Fictitious_defendants

A fictitious defendant is a person that cannot be identified by the plaintiff before a lawsuit is commenced. Commonly this person is identified as "John Doe" or " Jane Doe".

en.wikipedia.org/wiki/John_Doe

The names "John Doe" or "John Roe" for men, "Jane Doe" or "Jane Roe" for women, "Johnny Doe" and "Janie Doe" for children, or just "Doe" ...

caselaw.findlaw.com/hi-intermediate-court-of-appeals/1642298.html

Aug 20, 2013 ... John Does 1–5, Jane Does 1–5, Doe Corporations 1–5, Doe Partnerships 1–5, Doe Entities 1–5, and Doe Governmental Units 1–5, ...

www.marylandmissing.com/unidentifiedpersons.html

John and Jane does in Maryland. ... Jane Doe homicide still unsolved after 26 years, Susan Ingram, Community Times, January 10, 2003 .... Found 1/5/2005 ...

www.cleveland.com/open/index.ssf/2010/06/ohio_supreme_court_clarifies_r.html

Jun 8, 2010 ... Ohio Supreme Court clarifies rules on 'John Doe' lawsuits. Posted on ... COLUMBUS, Ohio – John and Jane Doe get sued a lot. But they're ...

www.ohioattorneygeneral.gov/Law-Enforcement/Local-Law-Enforcement/Unidentified-Remains/All-Unidentified-Remains

Results 1 - 10 ... John Doe, # 2027 · Picture of John Doe, # 2027 ... Picture of Jane Doe, #2004. Incident location: West ... Incident date: 1/5/2009. Case number: ...

answers.justia.com/question/2010/10/24/definition-does-1-100-inclusive-726

Oct 24, 2010 ... A: "Does", "John Doe" or "Jane Doe" are placeholder name used in legal actions for people whose true identity is unknown or must be withheld ...

www.reddit.com/r/gratefuldoe/comments/6inkl5/as_of_2017_they_have_identified_14_jane_and_john

This subreddit was originally created as an open forum to discuss and share information pertaining to the Grateful Doe case. It is now dedicated ...

purrr.tidyverse.org/reference/cross.html

... operations. cross_df() returns the output in long format just as expand.grid() does. ... pass each one to paste() data <- list( id = c("John", "Jane"), greeting = c(" Hello. ... function filter <- function(x, y) x >= y cross2(1:5, 1:5, .filter = filter) %>% str ().