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www.algebra.com/algebra/homework/Exponents/Exponents.faq.question.174506.html

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Q:
Solve the following equation for A : 2A/3 = 8 + 4A ?

A:
2A/3=8 +4A . if multiply by (3 ) to 2A/3=8 +4A then 2A =24+12A. now 0=24+10A or 10A=24 now A=2.4.
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Q:
solve the following equation for A : 2A/3 = 8 + 4A

A:
First, multiply both sides by 3 , to get 2A =24+12A. Put the As on one side, -10A=2
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Can You Solve The Following Equation For A : 2A/3 = 8 + 4A ?

A:
2A/3 = 8 + 4A 2A = 24 + 12A -24 = 12A - 2A -24 = 10A A = -2 2/5
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Solve the following equation for A : 2A/3 = 8 + 4A A. -2.4 B. 2.4...

A:
2A/3 = 8 + 4A First, multiply through by the denominator. 3 (2A/3) = 3 (8 ) + 3 (4A ) 2A = 24 + 12A Collect the variables on the left. 2A - (12A) = 24 + 12A - (12A)1...
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Solve the following equation for A2A3 equals 8 plus 4A ?

A:
2a ^3 =8 +4a . 2a ^3-4a-8=0. a^3-2a-4=0. It occurred to me just now by looking at the equation that a=2 would work. And it does. So that's your answer.
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