www.khanacademy.org/math/algebra/one-variable-linear-equations/alg1-two-steps-equations-intro/v/solving-equations-1

It takes **two steps** because he first has to subtract **2** from both sides and then
multiply both sides by 4. ... Prepare with these 11 lessons on **Solving equations**.
.... Since you have **fractions** in every term, the first thing to do is find the common ...

www.khanacademy.org/math/cc-seventh-grade-math/cc-7th-variables-expressions/cc-8th-two-step-equations-dec-frac/v/two-step-equations-with-decimals-and-fractions

Learn how to **solve** equations that involve decimals and **fractions**. The equations
shown in this video are called "**two**-**step**" **equations** because they each take two ...

www.khanacademy.org/math/cc-seventh-grade-math/cc-7th-variables-expressions/cc-8th-two-step-equations-dec-frac/e/two-step-equations-with-decimals-and-fractions

Practice **solving equations** that take **two steps** to **solve**. These problems involve
arithmetic with **fractions** and decimals.

www.varsitytutors.com/prealgebra-help/two-step-equations-with-fractions

Example Question #1 : **Two Step Equations With Fractions**. **Solve** for x: 12x+34=9
. Possible Answers: 1614. 412. 1634. 1612. Correct answer: 1612. Explanation:.

www.varsitytutors.com/hotmath/hotmath_help/topics/solving-two-step-linear-equations-with-fractions

**Solving** Two-Step Linear **Equations with Fractions**. A **two**-**step equation** has two
different operations. To **solve** a **two**-**step equation**, use inverse operations to ...

www.algebra-class.com/algebra-equations.html

The next two examples will demonstrate how to **solve two**-**step equations** when
the coefficient is a **fraction** or when you have a divisor. Let's take a look!

www.montereyinstitute.org/courses/DevelopmentalMath/COURSE_TEXT2_RESOURCE/U10_L1_T2_text_final.html

That's because this **equation** contains not just a variable but also **fractions** and
terms ... This is a multi-**step equation**, one that takes several **steps** to **solve**. ...
Subtract **2** from both sides of the **equation** to get the term with the variable by
itself.